Python簡單查詢用戶
一，第一種：
采用文件中contact.txt中第一行讀出後，將其分割成列表，然後對其判斷，但是不支持部門查詢。
#!/usr/bin/env python
while True:
name=raw_input('please input name:')
if name == 'small':
while True:
password=raw_input('please input password:')
if password == '123':
print 'welcome login system'
while True:
input=raw_input('please input employee name:')
f=open('contact.txt','r')
match=0
for i in f.readlines():
if input == i.split(" ")[1]:
print i
match=1
if match==0:
print "user not found,please input"
f.close()
#break
else:
print 'password is wrong,try again'
break
第二種：將文件中每行讀出後成字符串的形式，因此支持各個字段查詢。
#!/usr/bin/python
while True:
input = raw_input("please input your username:")
if input == 'small':
password = raw_input("please input your pass:")
p = '123'
while password != p:
password = raw_input("wrong passwd,input again:")
else:
print "welcome login to linux!"
while True:
match_yes = 0
input = raw_input("\033[32mPlease input name whom you want to search:\33[0m")
contact_file = file('contact_list.txt','r')
while True:
line = contact_file.readline()
if len(line) == 0:break
if input != "" and input in line:
print "match item: \33{36,1m%s\033[0m" % line
match_yes = 1
if match_yes == 0 :print "no match item found"
第三種：用字典的方式來實現
#!/usr/bin/env python
f=file('contact.txt')
personal={}
for line in f.readlines():
name= line.split()[0]
personal[name]=line
while True:
f=file('contact.txt')
personal={}
for line in f.readlines():
name= line.split()[0]
personal[name]=line
while True:
input=raw_input('please input username:').strip()
if len(input) == 0:continue
if input in personal:
#if personal.has_key(input):
#print 'username information: %s' %personal.get(input)
print 'username information: %s' %personal[input]
else:
print '%s not found,please input' %input
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