Android平台下的AES加密和Java平台下的運行結果不同的解決辦法

實現Android和Java互相加解密

完美支持中文

跨平台這種實現

還是一個原則

不要對參數采用默認實現

否則難以互通

核心函數如下，Android和java均如此

1. public static final String VIPARA = "0102030405060708";
2. public static final String bm = "GBK";

1. public static String encrypt(String dataPassword, String cleartext)
2. throws Exception {
3. IvParameterSpec zeroIv = new IvParameterSpec(VIPARA.getBytes());
4. SecretKeySpec key = new SecretKeySpec(dataPassword.getBytes(), "AES");
5. Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
6. cipher.init(Cipher.ENCRYPT_MODE, key, zeroIv);
7. byte[] encryptedData = cipher.doFinal(cleartext.getBytes(bm));
9. return Base64.encode(encryptedData);
10. }
12. public static String decrypt(String dataPassword, String encrypted)
13. throws Exception {
14. byte[] byteMi = Base64.decode(encrypted);
15. IvParameterSpec zeroIv = new IvParameterSpec(VIPARA.getBytes());
16. SecretKeySpec key = new SecretKeySpec(dataPassword.getBytes(), "AES");
17. Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
18. cipher.init(Cipher.DECRYPT_MODE, key, zeroIv);
19. byte[] decryptedData = cipher.doFinal(byteMi);
21. return new String(decryptedData,bm);
22. }

Base64從網上找的工具類

1. package com.bao;
3. import java.io.ByteArrayOutputStream;
4. import java.io.IOException;
5. import java.io.OutputStream;
9. public class Base64 {
10. private static final char[] legalChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/".toCharArray();
11. /**
12. * data[]進行編碼
13. * @param data
14. * @return
15. */
16. public static String encode(byte[] data) {
17. int start = 0;
18. int len = data.length;
19. StringBuffer buf = new StringBuffer(data.length * 3 / 2);
21. int end = len - 3;
22. int i = start;
23. int n = 0;
25. while (i <= end) {
26. int d = ((((int) data[i]) & 0x0ff) << 16)
27. | ((((int) data[i + 1]) & 0x0ff) << 8)
28. | (((int) data[i + 2]) & 0x0ff);
30. buf.append(legalChars[(d >> 18) & 63]);
31. buf.append(legalChars[(d >> 12) & 63]);
32. buf.append(legalChars[(d >> 6) & 63]);
33. buf.append(legalChars[d & 63]);
35. i += 3;
37. if (n++ >= 14) {
38. n = 0;
39. buf.append(" ");
40. }
41. }
43. if (i == start + len - 2) {
44. int d = ((((int) data[i]) & 0x0ff) << 16)
45. | ((((int) data[i + 1]) & 255) << 8);
47. buf.append(legalChars[(d >> 18) & 63]);
48. buf.append(legalChars[(d >> 12) & 63]);
49. buf.append(legalChars[(d >> 6) & 63]);
50. buf.append("=");
51. } else if (i == start + len - 1) {
52. int d = (((int) data[i]) & 0x0ff) << 16;
54. buf.append(legalChars[(d >> 18) & 63]);
55. buf.append(legalChars[(d >> 12) & 63]);
56. buf.append("==");
57. }
59. return buf.toString();
60. }
62. private static int decode(char c) {
63. if (c >= 'A' && c <= 'Z')
64. return ((int) c) - 65;
65. else if (c >= 'a' && c <= 'z')
66. return ((int) c) - 97 + 26;
67. else if (c >= '0' && c <= '9')
68. return ((int) c) - 48 + 26 + 26;
69. else
70. switch (c) {
71. case '+':
72. return 62;
73. case '/':
74. return 63;
75. case '=':
76. return 0;
77. default:
78. throw new RuntimeException("unexpected code: " + c);
79. }
80. }
82. /**
83. * Decodes the given Base64 encoded String to a new byte array. The byte
84. * array holding the decoded data is returned.
85. */
87. public static byte[] decode(String s) {
89. ByteArrayOutputStream bos = new ByteArrayOutputStream();
90. try {
91. decode(s, bos);
92. } catch (IOException e) {
93. throw new RuntimeException();
94. }
95. byte[] decodedBytes = bos.toByteArray();
96. try {
97. bos.close();
98. bos = null;
99. } catch (IOException ex) {
100. System.err.println("Error while decoding BASE64: " + ex.toString());
101. }
102. return decodedBytes;
103. }
105. private static void decode(String s, OutputStream os) throws IOException {
106. int i = 0;
108. int len = s.length();
110. while (true) {
111. while (i < len && s.charAt(i) <= ' ')
112. i++;
114. if (i == len)
115. break;
117. int tri = (decode(s.charAt(i)) << 18)
118. + (decode(s.charAt(i + 1)) << 12)
119. + (decode(s.charAt(i + 2)) << 6)
120. + (decode(s.charAt(i + 3)));
122. os.write((tri >> 16) & 255);
123. if (s.charAt(i + 2) == '=')
124. break;
125. os.write((tri >> 8) & 255);
126. if (s.charAt(i + 3) == '=')
127. break;
128. os.write(tri & 255);
130. i += 4;
131. }
132. }
134. }